先化简,再求值:x/x+2-(x^2+2x+1)/x+2÷x^2-1/x-1,其中x=根号3-2
先化简,再求值:x/x+2-(x^2+2x+1)/x+2÷x^2-1/x-1,其中x=根号3-2
:x/x+2-(x^2+2x+1)/x+2÷x^2-1/x-1,其中x=根号3-2
=x/(x+2)-(x+1)²/(x+2)×(x-1)/(x+1)(x-1)
=x/(x+2)-(x+1)/(x+2)
=-1/(x+2)
=-1/(√3-2+2)
=-√3/3;
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祝学习进步
先化简,再求值:x^2+2x+1/x+2 ÷x^2-1/x-1 - 1/x+2,其中x=根号2
x^2+2x+1/x+2 ÷x^2-1/x-1 - 1/x+2,其中x=根号2
=（x+1）²/(x+2)×(x-1)/(x+1)(x-1)-1/(x+2)
=(x+1)/(x+2)-1/(x+2)
=x/(x+2)
=√2/(√2+2)
=√2(2-√2)/(4-2)
=(2√2-2)/2
=√2-1;
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祝学习进步
先化简再求值[[(x2+2x+1)/(x+2)]÷[(x2-1)/(x-1)]-x/(x+2)其中x=√3-2
原式=(x+1)²/(x+2)÷(x+1)(x-1)/(x-1)-x/(x+2)
=(x+1)²/(x+2)÷(x+1)-x/(x+2)
=(x+1)/(x+2)-x/(x+2)
=(x+1-x)/(x+2)
=1/(x+2)
=1/(√3-2+2)
=√3/3
先化简,再求值:x/x+2-x2;+2x+1/x+2÷x2;-1/x-1其中x=√3-2
您好：
x/x+2-x2;+2x+1/x+2÷x2;-1/x-1
=x/(x+2)-(x+1)^2/(x+2)÷(x+1)(x-1)/(x-1)
=x/(x+2)-(x+1)/(x+2)
=-1/(x+2)
=-1/(√3-2+2)
=-1/√3
=-√3/3
如果本题有什么不明白可以追问，如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助，答题不易，请谅解，谢谢。
祝学习进步！
先化简,再求值:x^2+2x+1/x+2 ÷x^2-1/x-1 - 1/x+2，其中x=1/2
x^2+2x+1/x+2 ÷x^2-1/x-1 - 1/x+2
=(x＋1)²／(x＋2)÷(x＋1)(x－1)／(x－1)- 1/(x+2)
=(x＋1)²／(x＋2)×1／(x＋1)- 1/(x+2)
=(x＋1)／(x＋2) －1/(x+2)
=x＋1－1／x＋2
=x／x＋2
把x=1/2代入
原式=x／x＋2
=1／2÷(1／2＋2)
=1／5
1.先化简，再求值：x/x+2-x²+2x+1/x+2 ÷ x²-1/x-1，其中x=√3-2
x/x+2-x²+2x+1/x+2 ÷ x²-1/x-1
=x／(x＋2)－(x＋1)²／(x＋2) ÷(x＋1)(x－1)／(x－1)
=x／(x＋2)－(x＋1)²／(x＋2) ×1／(x＋1)
=x／(x＋2)－(x＋1)／(x＋2)
=(x－x－1)／(x＋2)
=﹣1／(x＋2)
将x=√3-2代入
原式=﹣1／(x＋2)
=﹣1／√3－2＋2
=﹣√3／3
先化简,再求值:(x^2/(x-1)-2x/(1-x))÷x/x-1,其中x=根号2+1
您好：
(x^2/(x-1)-2x/(1-x))÷x/x-1
=(x²+2x)/(x-1)÷x/(x-1)
=x(x+2)÷x
=x+2
=√2+1+2
=√2+3
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祝学习进步！
先化简再求值 x/(x+2)-(x²+2x)/(x-5)÷[(x²-1)/(x-1)] 其中x=根号三-2
=x/(x+2)-x（x+2)/(x-5)÷（x+1）
=x/(x+2)-x（x+2)/(x-5)（x+1）
=[x（x-5）（x+1）-x（x+2）（x+2）]/(x+2)(x-5)(x+1)
=(-8x^2-9x)/(x+2)(x-5)(x+1)
先化简，再求值:x^2-1/(x+2)(x-1)÷[1+1/(x^2+2x)]
(x^2-1)/(x+2)(x-1) ÷ [1+1/(x^2+2x)]
=(x+1)(x-1)/(x+2)(x-1) ÷ [(x^2+2x+1)/(x^2+2x)]
=(x+1)(x-1)/(x+2)(x-1) * (x^2+2x)/(x^2+2x+1)
=(x+1)(x-1)/(x+2)(x-1) * x(x+2)/(x+1)^2
=x /(x+1)
先化简,再求值:[3/(x-1)-x-1]/[(x-2)/(x²-2x+1)],其中,x=-根号2
[3/(x-1)-x-1]/[(x-2)/(x²-2x+1)]
=[3/(x-1)-(x+1)(x-1)/(x-1)]/[(x-2)/(x-1)²]
=(3-x²+1)/(x-1)]/[(x-2)/(x-1)²]
=(4-x²)/(x-1)]/[(x-2)/(x-1)²]
=-(x²-4)/(x-1)]/[(x-2)/(x-1)²]
=-[(x-2)(x+2)/(x-1)]/[(x-2)/(x-1)²]
=-(x-2)(x+2)/(x-1)*(x-1)²/(x-2)
=-(x+2)(x-1)
=-(-√2+2)(-√2 -1)
=(-√2+2)(√2+1)
=-2-√2+2√2+2
=√2
