Question

3分之2x-0.1-6分之5x-0.1=0.1

Answer 1

解方程∶
原式为∶
(2x-0.1)/3-(5x-0.1)/6=0.1
1. 去分母∶
方程两边同乘以6得∶
2(2x-0.1)-(5x-0.1)=0.6
2. 去括号得∶
4x-0.2-5x+0.1=0.6
3. 移项得∶
4x-5x=0.6+0.2-0.1
4. 合并同类项得∶
-x=0.7
x=-0.7

Answer 2

3分之2x-0.1-6分之5x-0.1=0.1
2/3x-1/10-5/6x-1/10=1/10
4/6x-5/6x=1/10+2/10
-1/6x=3/10
x=-3/10·6
x=-5分之9
x=-1.8

Answer 3

3分之2x-0.1-6分之5x-0.1=0.1
4x-0.2-5x+0.1=0.6
-x=0.6+0.1
x=-0.7