Question

用配方法解，已知x²+y²＋xy-3y+3=0，求x的y次方

Answer 1

原式配方得：x
+xy+y
/4
+
3y
/4-3y+3=0
即得：(x+
y/滑乎2)
+
3(y/2
-1)
=0
则有：燃让顷x+
y/2=0且y/2
-1=0
解得：皮陆y/2=1即y=2，x=-y/2=-1
所以：x的y次幂=(-1)
=1

Answer 2

原式配闭指清方得：轿前x²+xy+y²/4
+
3y²/4-3y+3=0
即得：(x+
y/2)²+
3(y/2
-1)²=0
则有：x+
y/2=0且y/2
-1=0
解得：y/2=1即y=2，逗返x=-y/2=-1
所以：x的y次幂=(-1)²=1