Question

计算级数前n项中(n=50)奇数项的和，输出级数最后两项之差绝对值1*2*3+2*3*4+3*4*5+……+n*(n+1)*(n+2)？

Answer 1

#include <stdio.h>
void main()
{
int a1, a2;
long int result = 0;
int i;
for(i = 1; i <= 50; i++){
a1 = i;
a2 = i + 1;
if((i % 2) == 1){
result += a1 * a2;
}
}
printf("%d\n", result);
}