已知x^2+y^2-4x-2y-4=0,则2x+3y+3/x+3的最大值是
已知x^2+y^2-4x-2y-4=0,则2x+3y+3/x+3的最大值是过程尽量详细，谢谢...
已知x^2+y^2-4x-2y-4=0,则2x+3y+3/x+3的最大值是 过程尽量详细，谢谢
展开
1个回答
展开全部
x² + y² - 4x - 2y - 4 = 0
x² + y² - 4x - 2y = 4
x² - 4x + __ + y² - 2y + __ = 4
x² - 4x + _4_ + y² - 2y + _1_ = 4 + 4 + 1
(x - 2)² + (y - 1)² = 9
The center is (2,1) and the radius is 3.
-1<=x<=5, --->(1)
-2<=y<=4 ---->(2)
令 2x+3y+3/x+3=K
x=3(y+1-K)/(K-2) --->(3)
-1<=3(y+1-K)/(K-2)<=5 --->(4)
y=4 x=2, K有最大值 19/5
x² + y² - 4x - 2y = 4
x² - 4x + __ + y² - 2y + __ = 4
x² - 4x + _4_ + y² - 2y + _1_ = 4 + 4 + 1
(x - 2)² + (y - 1)² = 9
The center is (2,1) and the radius is 3.
-1<=x<=5, --->(1)
-2<=y<=4 ---->(2)
令 2x+3y+3/x+3=K
x=3(y+1-K)/(K-2) --->(3)
-1<=3(y+1-K)/(K-2)<=5 --->(4)
y=4 x=2, K有最大值 19/5
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
