三道因式分解,要过程,谢谢啦
1个回答
展开全部
(1)
4b^2.c^2-(b^2+c^2)^2
=(2bc-b^2-c^2)(2bc+b^2+c^2)
=-(b-c)^2.(b+c)^2
(2)
16m^4-72m^2+81
=(4m)^2 - 2(4m)(9) + 9^2
=(4m^2-9)^2
=(2m-3)^2.(2m+3)^2
(3)
-(a+1)^2-2(a^2-1)-(a-1)^2
=-[(a+1)^2+2(a-1)(a+1)+(a-1)^2]
=-[( a+1+ a-1)^2]
=-4a^2
4b^2.c^2-(b^2+c^2)^2
=(2bc-b^2-c^2)(2bc+b^2+c^2)
=-(b-c)^2.(b+c)^2
(2)
16m^4-72m^2+81
=(4m)^2 - 2(4m)(9) + 9^2
=(4m^2-9)^2
=(2m-3)^2.(2m+3)^2
(3)
-(a+1)^2-2(a^2-1)-(a-1)^2
=-[(a+1)^2+2(a-1)(a+1)+(a-1)^2]
=-[( a+1+ a-1)^2]
=-4a^2
更多追问追答
追问
2(a²-1)为什么变成了2(a-1)(a-1)?
亲,可以解释一下吗?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询