求英语大神翻译此段!!请不要用有道等网络工具直译😂谢谢谢谢 2.分析结果 依次 50
求英语大神翻译此段!!请不要用有道等网络工具直译😂谢谢谢谢2.分析结果依次取阀值=1,0.617,0.594,0.524,0.476,0.406,根据阀值...
求英语大神翻译此段!!请不要用有道等网络工具直译😂谢谢谢谢
2.分析结果
依次取阀值=1,0.617,0.594,0.524,0.476,0.406,根据阀值原则,可以依次得到相应的入截矩阵,(大于或等于l的元素均记为1,小于l的元素记为0,当l=1时,入截矩阵R1为
此时第四行上的元素除对角线上为0外,其余都为0,故第四行对应的评价对象A4为最优,也就是1985年的财政支出结构为最优。
重复此过程,可得出最优元素依次是A4、A3、A2、A1。也就是说,财政支出的合理性由优至劣的排序为1985年1975年1965年1955年。 展开
2.分析结果
依次取阀值=1,0.617,0.594,0.524,0.476,0.406,根据阀值原则,可以依次得到相应的入截矩阵,(大于或等于l的元素均记为1,小于l的元素记为0,当l=1时,入截矩阵R1为
此时第四行上的元素除对角线上为0外,其余都为0,故第四行对应的评价对象A4为最优,也就是1985年的财政支出结构为最优。
重复此过程,可得出最优元素依次是A4、A3、A2、A1。也就是说,财政支出的合理性由优至劣的排序为1985年1975年1965年1955年。 展开
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The rationality of the object evaluation of the at the time of the elements of the principle, according to the analysis result successively thresholding =1,0.617,0.594,0.524,0.476,0.406 threshold value of can be obtained in turn by the corresponding A-cut matrix (greater than or equal to l elements are denoted 1, less than 1 0, when l = 1, cut matrix R1 is element in addition to diagonal is 0, and the rest is 0, so the fourth row corresponds to the A4 is optimal, but also is 1985 years of fiscal expenditure structure is optimal. Repeat this process can obtain the optimal element in turn is A4, A3, A2, A1. It is said that fiscal expenditure from superior to inferior sort for the 1985 1975 1965 1955 years.
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