Question

这道题怎么算都算不出来答案，求解具体过程！

求解，最后算的时候我算的结果是0。。。

Answer 1

如下

追问

谢谢谢谢！我知道自己错哪里了！

Answer 2

1- sinx

=1- 2sin(x/2).cos(x/2)
= [sin(x/2)]^2 -2sin(x/2).cos(x/2) + [cos(x/2)]^2
=[sin(x/2) - cos(x/2) ]^2
∫(0->π) √(1-sinx) dx
=∫(0->π) |sin(x/2) - cos(x/2) |dx
=∫(0->π/2) [cos(x/2) - sin(x/2) ]dx + ∫(π/2->π) [sin(x/2) - cos(x/2) ]dx
=4(√2-1)

追问

非常感谢！！^_^