Question

(2x-1)/5+(3y-2)/4=2 和 (3x+1)/3-(3y+2)/4=4/3二元一次方程的解

一定要快啊！！

Answer 1

(2x-1)/5+(3y-2)/4=2
两边乘20
8x-4+15y-10=40
8x+15y=54 (1)

(3x+1)/3-(3y+2)/4=4/3
两边乘12
12x+4-9y-6=16
12x-9y=18
4x-3y=6 (2)
(1)+(2)×5
8x+15y+20x-15y=54+30
28x=84
x=3
y=(4x-6)/3=2

Answer 2

[x,y]=solve ('(2*x-1)/5+(3*y-2)/4=2 ','(3*x+1)/3-(3*y+2)/4=4/3','x,y')

Matlab程序运行结果:

x =

3

y =

2

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