Question

数学11,12,13

Answer 1

11(1)原式=(6 + 1/5 - 4)•√3
=(2 + 1/5)•√3
=(11/5)√3

追答

(2)原式=(2 - 1 + 2/3)•√2x
=(1 + 2/3)•√2x
=(5/3)√2x

12、原式=√49•2 - 2√25•3 - √9•3 + √64•2
=7√2 - 2•5√3 - 3√3 + 8√2
=15√2 - 10√3 - 3√3
=15√2 - 13√3

13、原式=(a/3)√a - 2a²√(1•a)/a² + (2a/3)√a
=(a/3 + 2a/3)√a - (2a²/a)√a
=a√a - 2a√a
=-a√a