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求帮忙解答一道微积分的计算题,要过程 20
1个回答
展开全部
z = ln[(x-y)/(x+y)] = ln|x-y| - ln|x+y|
∂z/∂x = 1/(x-y) - 1/(x+y) = 2y/(x^2-y^2)
∂z/∂y = -1/(x-y) - 1/(x+y) = -2x/(x^2-y^2)
dz = 2(ydx-xdy)/(x^2-y^2)
∂z/∂x = 1/(x-y) - 1/(x+y) = 2y/(x^2-y^2)
∂z/∂y = -1/(x-y) - 1/(x+y) = -2x/(x^2-y^2)
dz = 2(ydx-xdy)/(x^2-y^2)
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