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以图为准吧
取DC中点T,连MT、TA,由中位线定理,MT||EC,下证MT垂直于AM。
图中△AED相似于△ADC(∠BAD=∠DAC,∠AED=∠ADC)
=>AE/ED=AD/DC
=>AE/(0.5*ED)=AD/(0.5*DC)=>AE/EM=AD/DT=>△AEM相似于△ADT
=>AE/AM=AD/AT and ∠EAM=∠DAT =>AE/AD=AM/AT and ∠EAD=∠MAT
=> △AED相似于△AMT => ∠AMT = 90 => AM 垂直于EC
取DC中点T,连MT、TA,由中位线定理,MT||EC,下证MT垂直于AM。
图中△AED相似于△ADC(∠BAD=∠DAC,∠AED=∠ADC)
=>AE/ED=AD/DC
=>AE/(0.5*ED)=AD/(0.5*DC)=>AE/EM=AD/DT=>△AEM相似于△ADT
=>AE/AM=AD/AT and ∠EAM=∠DAT =>AE/AD=AM/AT and ∠EAD=∠MAT
=> △AED相似于△AMT => ∠AMT = 90 => AM 垂直于EC
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