这个变量可分离微分方程为什么和我解的不一样?
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你应该这么整理
lnu+ln(x+1)=lnC-x
u(x+1)=Ce^(-x)
所以其实是一样的,只是你的不够简练
lnu+ln(x+1)=lnC-x
u(x+1)=Ce^(-x)
所以其实是一样的,只是你的不够简练
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years old, the key is to get to her now all didn't go to the nursing home, she said I ask her, because I make money, want to know the truth? I haven't asked her, she before she give me, she said because cousin also not every month, but the key is she wanted so much to do
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du/dx = -[(x+2)/(x+1)] u
∫du/u = -∫[(x+2)/(x+1)] dx
ln|u| = -∫[1+ 1/(x+1)] dx
=-x -ln|x+1| +C'
u = e^[-x -ln|x+1| +C']
= [C/(x+1)].e^(-x)
∫du/u = -∫[(x+2)/(x+1)] dx
ln|u| = -∫[1+ 1/(x+1)] dx
=-x -ln|x+1| +C'
u = e^[-x -ln|x+1| +C']
= [C/(x+1)].e^(-x)
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