Question

在直角坐标系XOY中，已知圆心在第二象限，半径为2备根号2的园C

Answer 1

(a^2-6ab+9b^2)/a^2-2ab÷(5b^2/a-2b -a-2b)-1/a

=(a-3b)²/a(a-2b)÷[5b²/(a-2b)-(a²-4b²)/(a-2b)]-1/a

=(a-3b)²/a(a-2b)÷(9b²-a²)/(a-2b)-1/a=(a-3b)²/a(a-2b)×[-(a-2b)]/(a+3b)(a-3b)-1/a

=-(a-3b)/a(a+3b)-1/a

=-(a-3b)/a(a+3b)-(a+3b)/a(a+3b)

=-2a/a(a+3b)

=-2/(a+3b)

记得采纳我的答案哦，祝你学习进步