三元一次方程组 10
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2015-09-05 · 知道合伙人教育行家
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(2)
2a+b+c = 0 ......(1)
4a+2b+c = 5 ......(2)
2a-b+c = 4 ......(3)
(1)*2-(2)得:c=-5
将c=5代入(1)、(3)得:
2a+b-5=0 ......(4)
2a-b-5=4 ...... (5)
(4)+(5)得:
4a-10=4
a=7/2
将a=7/2、c=-5代入(1)得:
7+b-5=0
b=-2
(3)
x+y=8 .....(1)
y+z=-3 ......(2)
z+x=-1 ......(3)
{(1)+(2)+(3)}÷2得:
x+y+z = (8-3-1)/2 = 2 ......(4)
(4)-(2)得:x=2+3=5
(4)-(3)得:y=2+1=3
(4)-(1)得:z=2-8=-6
2a+b+c = 0 ......(1)
4a+2b+c = 5 ......(2)
2a-b+c = 4 ......(3)
(1)*2-(2)得:c=-5
将c=5代入(1)、(3)得:
2a+b-5=0 ......(4)
2a-b-5=4 ...... (5)
(4)+(5)得:
4a-10=4
a=7/2
将a=7/2、c=-5代入(1)得:
7+b-5=0
b=-2
(3)
x+y=8 .....(1)
y+z=-3 ......(2)
z+x=-1 ......(3)
{(1)+(2)+(3)}÷2得:
x+y+z = (8-3-1)/2 = 2 ......(4)
(4)-(2)得:x=2+3=5
(4)-(3)得:y=2+1=3
(4)-(1)得:z=2-8=-6
追答
(2)
2a+b+c = 0 ......(1)
4a+2b+c = 5 ......(2)
2a-b+c = 4 ......(3)
(1)*2-(2)得:c=-5
将c=5代入(1)、(3)得:
2a+b-5=0 ......(4)
2a-b-5=4 ...... (5)
(4)+(5)得:
4a-10=4
a=7/2
将a=7/2、c=-5代入(1)得:
7+b-5=0
b=-2
(3)
x+y=8 .....(1)
y+z=-3 ......(2)
z+x=-1 ......(3)
{(1)+(2)+(3)}÷2得:
x+y+z = (8-3-1)/2 = 2 ......(4)
(4)-(2)得:x=2+3=5
(4)-(3)得:y=2+1=3
(4)-(1)得:z=2-8=-6
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