Question

求值tan(π／6-θ)+tan(π／6+θ)+√3tan(π／6-θ)tan(π／6+θ)

Answer 1

根号3 用两角和的正切公式展开tan(π／6-θ+π／6+θ)=a式/b式,将b式乘到等式左边再移项即得所求式子=根号3