已知x^2减5x加1=0求x^2 x^2分之一的值
展开全部
x²-5x+1=0
x²=5x-1
x²+1/x²
=5x-1+1/(5x-1)
=(25x²-10x+1+1）/(5x-1)
=(125x-25-10x+2)/(5x-1)
=(115x-23)/(5x-1)
=23X(5x-1)/(5x-1)
=23
x²=5x-1
x²+1/x²
=5x-1+1/(5x-1)
=(25x²-10x+1+1）/(5x-1)
=(125x-25-10x+2)/(5x-1)
=(115x-23)/(5x-1)
=23X(5x-1)/(5x-1)
=23
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
