化简sinx+sin(x+π/6)-cos(x+4π/3)
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2017-10-31
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sinx+sin(x+π/6)-cos(x+4π/3)
=sinx+sinxcos(π/6)+cosxsin(π/6)-cosxcos(4π/3)+sinxsin(4π/3)
=sinx+(√3/2)sinx+(1/2)cosx+(1/2)cosx-(√3/2)sinx
=sinx+cosx
=√2(sinxcos45°+cosxsin45°)
=√2sin(x+π/4)
=sinx+sinxcos(π/6)+cosxsin(π/6)-cosxcos(4π/3)+sinxsin(4π/3)
=sinx+(√3/2)sinx+(1/2)cosx+(1/2)cosx-(√3/2)sinx
=sinx+cosx
=√2(sinxcos45°+cosxsin45°)
=√2sin(x+π/4)
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