Question

（x+1）^2+（y-2）^2=4怎么化极坐标方程？

Answer 1

展开,然后用公式：x = ρ*cosθ,y = ρ*sinθ ,x²+y² = ρ²
(x+1)²+(y-2)²=4
x²+2x+1+y²-4y=0
ρ²+2ρcosθ+1-4ρsinθ=0