
3个回答
展开全部
(x+y)/(x³+y³+x+y)
=(x+y)/[(x+y)(x²-xy+y²)+(x+y)]
=1/(x²-xy+y²+1)
=1/[(x²+y²)-xy+1]
=1/(9-4+1)
=1/6
选C
=(x+y)/[(x+y)(x²-xy+y²)+(x+y)]
=1/(x²-xy+y²+1)
=1/[(x²+y²)-xy+1]
=1/(9-4+1)
=1/6
选C
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