
x-1分之x方减去x方减去x?
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[x²/(x-1)]-x²-x
= [x²/(x-1)]-[x²(x-1)/(x-1)]-[x(x-1)/(x-1)]
=(x²-x³+x²-x²+x)/(x-1)
=-(x³-x²-x)/(x-1)
=-x(x²-x-1)/(x-1)
= [x²/(x-1)]-[x²(x-1)/(x-1)]-[x(x-1)/(x-1)]
=(x²-x³+x²-x²+x)/(x-1)
=-(x³-x²-x)/(x-1)
=-x(x²-x-1)/(x-1)
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