Question

C#字符串转换成长日期格式

我有一个 string类型的 20100101 115812，请问如何把它转换成 yyyy-mm-dd hh:mm:ss ,该怎么转啊？
20100101 115812 转成 2010-01-01 11:58:12,知道的帮个忙，谢谢 ,下面的几种方式都试过了，转不了

Answer 1

DateTime dt=DateTime.Parse("20100101 115812");
可以用 dt.ToLocalTime()方法转成这种格式
也可以用string.Format("{0:yyyy-MM-dd hh:mm:ss}",dt)的方式

去掉中间的空格 绝对可以 ！！

Answer 2

format();方法

Answer 3

String text = "20100101 115812";
text = text.Insert(text.Length - 2, ":");
text = text.Insert(text.Length - 5, ":");
text = text.Insert(text.Length - 11, "-");
text = text.Insert(text.Length - 14, "-");
Console.WriteLine(text);

Answer 4

DateTime july28 = new DateTime(2010, 01, 01, 11, 58, 12);

string[] july28Formats = july28.GetDateTimeFormats();

// Print out july28 in all DateTime formats using the
// default culture.
foreach (string format in july28Formats)
{
System.Console.WriteLine(format);
}

IFormatProvider culture =
new System.Globalization.CultureInfo("fr-FR", true);
// Get the short date formats using the "fr-FR" culture.
string[] frenchJuly28Formats =
july28.GetDateTimeFormats('d', culture);

// Print out july28 in various formats using "fr-FR" culture.
System.Console.WriteLine("Starting fr-FR formats");
foreach (string format in frenchJuly28Formats)
{
System.Console.WriteLine(format);
}

Answer 5

Console.WriteLine(string.Format("{0:yyyy-MM-dd hh:mm:ss}",Convert.ToDateTime("2010-01-01 11:58:12")));