Question

已知x/2=y/3=z/4,求(x+y-2x)/(2x-y)的值

要过程

Answer 1

设x/2=y/3=z/4=k
则x=2k,
y=3k
z=4k。
(x+y-2x)/(2x-y)=（2k+3k-4k)/(4k-3k)
=1

Answer 2

由
x/2=y/3=z/4
得x=2y/3代入式子
(x+y-2x)/(2x-y)
（2y/3+y-2*2y/3)/(2*2y/3-y)=(y/3)/(y/3)=1