Question

因式分解（p+q）²-（p-q）²

要详细过程

Answer 1

根据平方差公式。
=（p+q+p-q)[p+q-(p-q)]
=2p×2q
=4pq

Answer 2

原式=(p^2+2pq+q^2)-(pp^2-2pq+q^2)=4pq

Answer 3

p2+ q2+2pq-[p2+q2-2pq]=p2+q2+2pq-p2-q2+2pq=4pq看样我的还是复杂了点

Answer 4

（p+q）²-（p-q）²
=（p+q+p-q）（p+q-p+q）
=2p·（2q)
=4pq