化简。谢谢
3个回答
展开全部
(1)
[x^(9/5) .y^(-6/5) ]^(-1/3) . ( xy)^(3/5)
=[x^(-3/5) .y^(2/5) ] . [ x^(3/5). y^(3/5) ]
= x^0 . y^1
=y
(2)
[x^6.y^2 ]^(-1/3) / [ y^(-1/3) ]^4
=[x^(-2).y^(-2/3) ] / y^(-4/3)
=x^(-2).y^(-2/3 + 4/3)
=x^(-2).y^(2/3)
[x^(9/5) .y^(-6/5) ]^(-1/3) . ( xy)^(3/5)
=[x^(-3/5) .y^(2/5) ] . [ x^(3/5). y^(3/5) ]
= x^0 . y^1
=y
(2)
[x^6.y^2 ]^(-1/3) / [ y^(-1/3) ]^4
=[x^(-2).y^(-2/3) ] / y^(-4/3)
=x^(-2).y^(-2/3 + 4/3)
=x^(-2).y^(2/3)
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询