Question

C++设计 定义一个矩形类Rect 急求啊

定义一个矩形类Rect，数据成员为length、height，要求有构造函数、析构函数，其成员函数area求矩形面积，利用主函数进行测试

Answer 1

[Rect.h]:
[code=cpp]
class Rect
{
public:
double height;
double width;

public:
Rect(void);
Rect(double height, double width);
~Rect(void);

void setHeight(double height);
void setWidth(double width);

double getHeight();
double getWidth();

double getArea();
};

[/code]

[Rect.cpp]:

[code=cpp]
#include "Rect.h"

Rect::Rect(void)
{
this->height = 0;
this->width = 0;
}

Rect::Rect(double height,double width){
this->setHeight(height);
this->setWidth(width);
}

Rect::~Rect(void)
{
}
void Rect::setHeight(double height)
{
if(0 < height)
{
this->height = height;
}
}

void Rect::setWidth(double width)
{
if(0 < width)
{
this->width = width;
}
}

double Rect::getHeight()
{
return this->height;
}
double Rect::getWidth()
{
return this->width;
}

double Rect::getArea()
{
return this->height * this->width;
}
[/code]

main.cpp :

[code=cpp]
#include <iostream>
#include "conio.h"

#include "Rect.h"

using namespace std;

int main(int argc, char* argv[])
{
Rect * rect = new Rect(10,20);

cout<<rect->getArea()<<endl;

getch();

return 0;
}
[/code]