高中数学求解。
1个回答
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(1)
(log<5>2017)^0 - (9/4)^(-1/2) + lg(3/10) + |lg3 -1|
= 1 -(4/9)^(1/2) + lg3 -1 -(lg3 -1)
= 1- 2/3
=1/3
(2)
{ [2^(1/3) . 3^(1/2) ]^6 - 2^(1/4) . 8^(0.25) }/ log<3>[ 27^(1/4)/ 3]
={ 2^2 . 3^3 - 2^(1/4) . 2^(3/4) }/ log<3>[ 3^(3/4)/ 3]
={ 2^2 . 3^3 - 2 }/ log<3>[ 3^(-1/4)]
= ( 108 -2 )/ (-1/4)
=-424
(log<5>2017)^0 - (9/4)^(-1/2) + lg(3/10) + |lg3 -1|
= 1 -(4/9)^(1/2) + lg3 -1 -(lg3 -1)
= 1- 2/3
=1/3
(2)
{ [2^(1/3) . 3^(1/2) ]^6 - 2^(1/4) . 8^(0.25) }/ log<3>[ 27^(1/4)/ 3]
={ 2^2 . 3^3 - 2^(1/4) . 2^(3/4) }/ log<3>[ 3^(3/4)/ 3]
={ 2^2 . 3^3 - 2 }/ log<3>[ 3^(-1/4)]
= ( 108 -2 )/ (-1/4)
=-424
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