Question

1×2+2×3+3×4+4×5+···+a(a+1)=?

Answer 1

1X2 +2X3 +3X4
= (1X2X3 +2X3X3 +3X4X3) /3
= [ 1X2X3 +2X3X(4-1) +3X4X(5-2) ] /3
= [ 1X2X3 -1X2X3 +2X3X4 -2X3X4 +3X4X5 ] /3
= 3X4X5 /3

1X2 +2X3 +3X4 +4X5
= (1X2X3 +2X3X3 +3X4X3 +4X5X3) /3
= [ 1X2X3 +2X3X(4-1) +3X4X(5-2) +4X5X(6-3) ] /3
= [ 1X2X3 -1X2X3 +2X3X4 -2X3X4 +3X4X5 -3X4X5 +4X5X6 ] /3
= 4X5X6 /3

规律就出来了，这个数列的公式就是
通项 a= n(n+1)
前n项数列和 S= n(n+1)(n+2)/3