Question

求解因式分解题

求详解(a^5+b^5)-(a^3b^2+a^2b^3)

Answer 1

原式=(a^5-a^3b^2)-(a^2b^3-b^5)
=a^3(a+b)(a-b)-b^3(a+b)(a-b)
=(a^3-b^3)(a+b)(a-b)

Answer 2

原式=(a^5-a³b²)+(a²b³-b^5)
=a³(a²-b²)+b³(a²-b²)
=(a²-b²)(a³+b³)
=(a+b)²(a-b)(a²-ab+b²)