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先化简,后求值
1个回答
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先化简再求值(x的2次方-2x+1分之x+1-x分之1)除x的2次方-1分之2
原式=[x/(x-1)²-1/(x-1)]*(x²-1)/2
=1/2[x/(x-1)²-1/(x-1)]*(x+1)(x-1)
=1/2[x(x+1)/(x-1)-(x+1)]
=(x²+x-x²+1)/2(x-1)
=(x+1)/2(x-1)
原式=[x/(x-1)²-1/(x-1)]*(x²-1)/2
=1/2[x/(x-1)²-1/(x-1)]*(x+1)(x-1)
=1/2[x(x+1)/(x-1)-(x+1)]
=(x²+x-x²+1)/2(x-1)
=(x+1)/2(x-1)
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