Question

Java中出现The constructor Dog1() is undefined是什么原因

class Dog{
private String name;
private int number;
private String sex;
Dog(String name,int number ,String sex)
{
this.name=name;
this.number= number;
this.sex=sex;
}
public void dogg()
{
System.out.println("狗狗叫叫："+this.name);
System.out.println("狗狗的年龄"+this.number);
System.out.println("狗狗的性别"+this.sex);
}
}

class Dog1 extends Dog
{
Dog1(String name,int age ,String sex)
{
super(name,age,sex);
}
public void special()
{
System.out.println("dog1会啃骨头，把妹");
}
}

public class dogStore {
public static void main(String[] args)
{
Dog1 mydog1=new Dog1();
mydog1.special();
}
}

Answer 1

Dog类中创建了有参构造方法，系统不会默认创建无参构造方法；
正确创建Dog对象：
Dog dog = new Dog("小白",2,"男")；

Answer 2

Dog1类里面要加个无参构造方法
Dog1(){}

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谢谢