展开全部
y'=n(sinx)^(n-1)cosxcosnx+(sinx)^n(-nsinnx)
=n(sinx)^(n-1)(cosxcosnx-sinxsinnx)
=n(sinx)^(n-1)cos(x+nx)
=n(sinx)^(n-1)(cosxcosnx-sinxsinnx)
=n(sinx)^(n-1)cos(x+nx)
更多追问追答
追答
sin²y=2/(x+1)-1
2sinycosyy'=-2/(x+1)²
y'=-1/(x+1)²√(2/(x+1)-1)√(2-2/(x+1))
=-1/(x+1)√((1-x)2x(x+1))
=-1/(x+1)√(2x-2x³)
e^2y=e^4x/(e^4x+1)
e^(-2y)=1+e^(-4x)
-2e^(-2y)y'=-4e^(-4x)
y'=2e^(-4x)/e^(-2y)=2/(e^4x+1)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询