设f(x)具有二阶连续导数,f(0)=0,f'(0)=0,f''(0)>0.
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在曲线y=f(x)上任意历蠢一点(x,f(x))(x不等于0)处做此告御曲线的切线:Y-f(x)=f'(x)(X-x),交x轴于点(u,0),
∴肢友陪u=x-f(x)/f'(x),
u'=1-[(f'(x)]^2-f(x)f''(x)]/[f'(x)]^2=f(x)f''(x)/[f'(x)]^2,
x→0时u→0-f'(x)/f''(x)→-f'(0)/f''(0)=0,
x...
∴肢友陪u=x-f(x)/f'(x),
u'=1-[(f'(x)]^2-f(x)f''(x)]/[f'(x)]^2=f(x)f''(x)/[f'(x)]^2,
x→0时u→0-f'(x)/f''(x)→-f'(0)/f''(0)=0,
x...
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