Question

求1到999能被3整除，且至少有一位数字是5的所有正整数的个数

Answer 1

一共有91个。实现的C++程序如下：

void testcode9()

{

int count = 0;

for (int i = 1; i <= 999; i++)

{

bool condition = ((i % 10) == 5) || (((i / 10) % 10) == 5) || (((i / 100) % 10) == 5);

if (condition && (i % 3 == 0))

{

cout << i << " ";

count++;

}

}

cout << endl;

cout << "The total num is " << count << endl;

}

最后的结果为：