tan(a-π/4)=1/2求(sina-2cosa)/(sina+cosa)的值
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tana=tan([a-π/4)+π/4]
=[tan(a-π/4)+π/4]/[1-tan(a-π/4)tan(π/4)]
=(1+1/2)/(1-1/2)
=3
(sina-2cosa)/(sina+cosa)
=(tana-2)/(tana+1)
=1/4
谢谢
=[tan(a-π/4)+π/4]/[1-tan(a-π/4)tan(π/4)]
=(1+1/2)/(1-1/2)
=3
(sina-2cosa)/(sina+cosa)
=(tana-2)/(tana+1)
=1/4
谢谢
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