Question

5x+3y+2z=24 6x+4y+z=28

xyz可以满足5x+3y+2z=24,6x+4y+z=28,求x,y,z,
xyz可以满足5x+3y+2z=24和6x+4y+z=28,求x,y,z,

Answer 1

如果未知数是正整数则有
5x + 3y + 2z = 34 .(1)
6x + 4y + z = 28 .(2)
(1) - (2)
z = 6 + x + y .代入(2)分别得到
7x + 5y = 22
5y = 22 - 7x
= 5*(4 - x) + 2*(1 - x)
x = 1
y = 3
z = 10