Question

根号24减根号0.5加2倍根号2/3的差减根号1/8减根号6的差怎么解

(√24-√0.5+2√(2/3))-(√(1/8)-√6)这个式子怎么解

Answer 1

√24-[√0.5+2√(2/3)]-√(1/8)-√6
=2√6-[√2/2+2√6/3]-√2/4-√6
=√6-[√2/2+2√6/3]-√2/4
=√6-√2/2-2√6/3-√2/4
=√6/3-3√2/4

Answer 2

=(2√6-√2/2+2√6/3)-(√2/2-√6)
=2√6+2√6/3+√6-√2/2-√2/2
=11√6/3-1

Answer 3

如果我没算错的话 等于 3分之5的根号6减四分之三的跟号二