Question

已知(x+2)^5=ax^5+bx^4+cx^3+dx^2+ex+f,则a+16b+4d+2f=

Answer 1

 

 

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Answer 2

(a+b)^n=Cn0·a^n+Cn1 ·a^n-1·b+…+Cnr·a^n-r·b^r+…+Cnn·b^n(n∈N﹢)

a=C(5,0)*2^0=1
b=C(5,1)*2^1=10
d=C(5,3)*2^3=80
f=C(5,5)*2^5=32

a+16b+4d+2f=1+160+320+64=545