Question

初三数学!急急急！！！

4（2x-1）^2=9(3x-2)^2 2分之1（x-2）^2+x-2=0
2（x-3）^2+（3x-x^2）=0 2分之1x（x-2）=x^2-4x+4

Answer 1

4(4x^2-4x+1)=9(9x^2-12x+4)
16x^2-16x+4=81x^2-108x+36
65x^2-92x+32=0
(13x-8)(5x-4)=0
x=13/8或x=0.8

1/2(x^2-4x+4)+x-2=0
0.5x^2-x=0
x（0.5x-1）=0
x=0或x=2

2(x^2-6x+9)+3x-x^2=0
x^2-9x+18=0
(x-3)(x-6)=0
x=3或x=6

0.5x^2-x=x^2-4x+4
0.5x^2-3x+4=0
0.5(x-2)(x-4)=0
x=2或x=4