求根号下（1-x^2）dx的积分【如图】求解呀～
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Try trig subsitution:
x = sinu
integral of sqrt(1-x^2) dx
= integral of cos^2 u du
= integral of (1/2)(1+cos2u) du
= (1/2)u + (1/4)sin2u + c
= (1/2)arcsinx + (1/2)xsqrt(1-x^2) + c
x = sinu
integral of sqrt(1-x^2) dx
= integral of cos^2 u du
= integral of (1/2)(1+cos2u) du
= (1/2)u + (1/4)sin2u + c
= (1/2)arcsinx + (1/2)xsqrt(1-x^2) + c
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