1-（x-1/1-x）²÷x²-x+1/x²-2x+1
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原式=1-[-(x-1)/(x-1)]²÷[(x²-x+1)/(x²-2x+1)]
=1-(-1)²×[(x²-2x+1)/(x²-x+1)]
=1-(x²-2x+1)/(x²-x+1)
=(x²-x+1-x²+2x-1)/(x²-x+1)
=x/(x²-x+1)
=1-(-1)²×[(x²-2x+1)/(x²-x+1)]
=1-(x²-2x+1)/(x²-x+1)
=(x²-x+1-x²+2x-1)/(x²-x+1)
=x/(x²-x+1)
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