
如图,已知在△ABC中,BD=DC,∠1=∠2,求证;AD平分∠BAC
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BD=BC=>∠DBC=∠DCB
∠1=∠2 =>∠ABC=∠ACB=>AB=AC
∠DBC=∠DCB =>△ABD≌△ACD
BD=CD
=>∠BAD=∠CAD=>AD平分∠BAC
∠1=∠2 =>∠ABC=∠ACB=>AB=AC
∠DBC=∠DCB =>△ABD≌△ACD
BD=CD
=>∠BAD=∠CAD=>AD平分∠BAC
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