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这两个是怎么因式分解成后面的式子的,要详细步骤
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2016-08-28 · 知道合伙人教育行家
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解: u^3/(u+1)
=[u^3/(u+1)+1/(u+1)]-1/(u+1)
=(u^3+1)/(u+1)-1/(u-1)
=[(u+1)(u^2-u+1)]/(u+1)-1/(u+1)
=u^2-u+1-1/(u+1)
1/(u^2-1)
=1/(u+1)(u-1)
=1/2[(u+1)/(u+1)(u-1)-(u-1)/(u-1)(u+1)]
=1/2[1/(u-1)-1/(u+1)]
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