Question

一元二次方程：3(x+1)^2=2(x+1)

写出解题过程和用哪种方法

Answer 1

3(x+1)^2=2(x+1)
3(x+1)^2-2(x+1)=0
(x+1)[(3(x+1)-2]=0(提取公因式)
(x+1)(3x+1)=0
x+1=0或3x+1=0
x1=-1
x2=-1/3

Answer 2

3(x+1)^2=2(x+1)
3(x+1)^2-2(x+1)=0
(x+1)(3x+3-2)=0
(x+1)(3x+1)=0
x+1=0
x=-1
3x+1=0
x=-1/3

Answer 3

3(x+1)^2=2(x+1)
3(x+1)^2-2(x+1)=0
(x+1)(3x+3-2)=0
x1=-1 x2=-1/3

Answer 4

3(x+1)^2-2(x+1)=0
(x+1)(3x+3-2)=0
(x+1)(3x+1)=0
x1=-1 x2=-1/3

Answer 5

3（x^2+2x+1)=2x+2
3x^2+6x+3=2x+2
3x^2+4x+1=0
用求根公式
得x1=-1,x2=-1/3

Answer 6

初中生阿？想简单点的话可以设 a=x+1
把式子变成 3a^2=2a