Question

用C#写一个 求1＋1/2+1/3+1/4+…….+1/100的值 再试求1－1/2+1/3－1/4+…….－1/100的值 我是新手越简单越

Answer 1

double s=0;
for(int i=1;i<=100;i++)
s+=(double)1/i;
//输出s

double s=0;
for(int i=1;i<=100;i++)
if(i%2==0)
s+=(double)1/i;
else
s-=(double)1/i;
//输出s

Answer 2

加法
double s = 0;
for (int i = 1; i <= 100; i++)
{
s +=(double) 1 / i;
}
Console.WriteLine(s);
Console.ReadLine();
减法
double s = 1;
for (int i = 2; i <= 100; i++)
{
s -=(double) 1 / i;
}
Console.WriteLine(s);
Console.ReadLine();