Question

若函数f（x）=x2-ax-b两个零点是2和3，则函数g（x）=bx2-ax-1的零点是？

Answer 1

函数f（x）=x2-ax-b两个零点是2和3则，a=5.b=-6,则函数g（x）=bx2-ax-1=-6x^2-5x-1,另函数等于0。得零点为，-1/3，-1/2

Answer 2

f(2)=4-2a-b=0
f(3)=9-3a-b=0
a=5,b=-6
g(x)=-6x^2-5x-1=0
x=-1/2 or x=-1/3