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令 u = xz,v = z-y,则 z = f(u,v), 两边对 x 求偏导,得
∂z/∂x = (∂f/∂u)(∂u/∂x) + (∂f/∂v)(∂v/∂x)
= (∂f/∂u)(z+x∂z/∂x) + (∂f/∂v)(∂z/∂x)
(1-x∂f/∂u-∂f/∂v)∂z/∂x = z∂f/∂u
∂z/∂x = z(∂f/∂u)/(1-x∂f/∂u-∂f/∂v);
z = f(u,v), 两边对 y 求偏导,得
∂z/∂y = (∂f/∂u)(∂u/∂y) + (∂f/∂v)(∂v/∂y)
= (∂f/∂u)(x∂z/∂y) + (∂f/∂v)(∂z/∂y-1)
(1-x∂f/∂u-∂f/∂v)∂z/∂y = -∂f/∂v
∂z/∂y = (-∂f/∂v)/(1-x∂f/∂u-∂f/∂v).
∂z/∂x = (∂f/∂u)(∂u/∂x) + (∂f/∂v)(∂v/∂x)
= (∂f/∂u)(z+x∂z/∂x) + (∂f/∂v)(∂z/∂x)
(1-x∂f/∂u-∂f/∂v)∂z/∂x = z∂f/∂u
∂z/∂x = z(∂f/∂u)/(1-x∂f/∂u-∂f/∂v);
z = f(u,v), 两边对 y 求偏导,得
∂z/∂y = (∂f/∂u)(∂u/∂y) + (∂f/∂v)(∂v/∂y)
= (∂f/∂u)(x∂z/∂y) + (∂f/∂v)(∂z/∂y-1)
(1-x∂f/∂u-∂f/∂v)∂z/∂y = -∂f/∂v
∂z/∂y = (-∂f/∂v)/(1-x∂f/∂u-∂f/∂v).
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