Question

x(y²-z²)+y(z²-x²)+z(x²-y²)

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Answer 1

x(y²-z²)+y(z²-x²)+z(x²-y²)
=xy²-xz²+yz²-yx²+z(x²-y²)
=z(x²-y²)-xy(x-y)-z^2(x-y)
=(x-y)(x+y)-xy(x-y)-z^2(x-y)
=(x-y)[(x+y)-xy-z^2]
=(x-y)(x+y-xy-z^2)