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解:设甲原有x元,乙原有y元:
第一步:x-(x/5)+{[y+(x/5)]/3}={[y+(x/5)]/3}*2
4*x/5+y/3+x/15=(y/3+x/15)*2
13*x/15+y/3=2*y/3+2*x/15
11*x/15=y/3
11*x=5*y
x=5*y/11
第二步:{[y+(x/5)]/3}*2=180
2y/3+2x/15=180
2y/3+2y/33=180
22y/33+2y/33=180
24y/33=180
y=180*33/24
y=247.5
x=5*247.5/11=112.5
第一步:x-(x/5)+{[y+(x/5)]/3}={[y+(x/5)]/3}*2
4*x/5+y/3+x/15=(y/3+x/15)*2
13*x/15+y/3=2*y/3+2*x/15
11*x/15=y/3
11*x=5*y
x=5*y/11
第二步:{[y+(x/5)]/3}*2=180
2y/3+2x/15=180
2y/3+2y/33=180
22y/33+2y/33=180
24y/33=180
y=180*33/24
y=247.5
x=5*247.5/11=112.5
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