求解答，很简单的三角形问题
5. A triangle PQR was given in which lengths&...
5. A triangle PQR was given in which lengths of two sides were given as QR = 12 , PR = 13 and the perimeter of the triangle was 32.
Col A: Measure of angle of Q
Col B: 90
最后就是让colA和colB比较大小，恩，我不知道这个题目要怎么算出Q,谢谢 展开
Col A: Measure of angle of Q
Col B: 90
最后就是让colA和colB比较大小，恩，我不知道这个题目要怎么算出Q,谢谢 展开
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由已知QR=12,PR=13,周长=32,所以PQ=7,所以cosQ=(7^2+12^2-13^2)/(2*7*12)
=1/7>0,所以Q<90°
=1/7>0,所以Q<90°
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